3.2.55 \(\int \frac {1}{(f+g x)^{3/2} (a+b \log (c (d+e x)^n))} \, dx\) [155]

Optimal. Leaf size=29 \[ \text {Int}\left (\frac {1}{(f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )},x\right ) \]

[Out]

Unintegrable(1/(g*x+f)^(3/2)/(a+b*ln(c*(e*x+d)^n)),x)

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Rubi [A]
time = 0.03, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {1}{(f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[1/((f + g*x)^(3/2)*(a + b*Log[c*(d + e*x)^n])),x]

[Out]

Defer[Int][1/((f + g*x)^(3/2)*(a + b*Log[c*(d + e*x)^n])), x]

Rubi steps

\begin {align*} \int \frac {1}{(f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )} \, dx &=\int \frac {1}{(f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )} \, dx\\ \end {align*}

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Mathematica [A]
time = 0.89, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{(f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[1/((f + g*x)^(3/2)*(a + b*Log[c*(d + e*x)^n])),x]

[Out]

Integrate[1/((f + g*x)^(3/2)*(a + b*Log[c*(d + e*x)^n])), x]

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Maple [A]
time = 0.17, size = 0, normalized size = 0.00 \[\int \frac {1}{\left (g x +f \right )^{\frac {3}{2}} \left (a +b \ln \left (c \left (e x +d \right )^{n}\right )\right )}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(g*x+f)^(3/2)/(a+b*ln(c*(e*x+d)^n)),x)

[Out]

int(1/(g*x+f)^(3/2)/(a+b*ln(c*(e*x+d)^n)),x)

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Maxima [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(g*x+f)^(3/2)/(a+b*log(c*(e*x+d)^n)),x, algorithm="maxima")

[Out]

-2*b*n*e*integrate(1/((b^2*d*g*log(c)^2 + 2*a*b*d*g*log(c) + a^2*d*g + (b^2*g*log(c)^2 + 2*a*b*g*log(c) + a^2*
g)*x*e + (b^2*g*x*e + b^2*d*g)*log((x*e + d)^n)^2 + 2*(b^2*d*g*log(c) + a*b*d*g + (b^2*g*log(c) + a*b*g)*x*e)*
log((x*e + d)^n))*sqrt(g*x + f)), x) - 2/((b*g*log((x*e + d)^n) + b*g*log(c) + a*g)*sqrt(g*x + f))

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Fricas [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(g*x+f)^(3/2)/(a+b*log(c*(e*x+d)^n)),x, algorithm="fricas")

[Out]

integral(sqrt(g*x + f)/(a*g^2*x^2 + 2*a*f*g*x + a*f^2 + (b*g^2*x^2 + 2*b*f*g*x + b*f^2)*log((x*e + d)^n*c)), x
)

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Sympy [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (a + b \log {\left (c \left (d + e x\right )^{n} \right )}\right ) \left (f + g x\right )^{\frac {3}{2}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(g*x+f)**(3/2)/(a+b*ln(c*(e*x+d)**n)),x)

[Out]

Integral(1/((a + b*log(c*(d + e*x)**n))*(f + g*x)**(3/2)), x)

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Giac [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(g*x+f)^(3/2)/(a+b*log(c*(e*x+d)^n)),x, algorithm="giac")

[Out]

integrate(1/((g*x + f)^(3/2)*(b*log((x*e + d)^n*c) + a)), x)

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Mupad [A]
time = 0.00, size = -1, normalized size = -0.03 \begin {gather*} \int \frac {1}{{\left (f+g\,x\right )}^{3/2}\,\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((f + g*x)^(3/2)*(a + b*log(c*(d + e*x)^n))),x)

[Out]

int(1/((f + g*x)^(3/2)*(a + b*log(c*(d + e*x)^n))), x)

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